British Go Journal No. 20. July 1973. Page 6.
The problem below appears in Go Letter No 4 of the Matsuda Go Letters. The answer is in Go Letter No 5 and is wrong.
Diagram 1 |
The answer given is white A, black E and white B. This way the group lives, but only by an error on the part of black. When white has played A, black should reply at B and then the best that white can gain is seki. White has three choices as to his next move: C, D or E.
C - This secures one eye, but black can escape by playing at E and then a double atari at D would result in damezumari.
D - This move puts the two white stones into atari, but this does not work because black simple palys at E and connects his stones leaving white to take the two stones, only to have his stone taken back and lose his group, once again by damezumari.
E - This is the better of the three moves available to white, but this results in a seki. Black plays at C putting the three white stones into atari, white must connect. Then black plays at H and the result is seki.
It is not correct to play A as the first move, the vital point is elesewhere. In fact at the same point that black takes to kill the white group.
At the point of B then, no matter how hard black tries, the white group is alive. This shows how just a miscalculation in the order of moves can lead to total disaser.
The moves discussed as a game-file in SGF format.